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Opening a URL from an iOS FireMonkey application

The Hacker's Corner – Q: How do you open a URL in Safari on the iPhone using FireMonkey? A: You use UIApplication.sharedApplication.openUrl Below is a very simple unit that will do the code. Just create an iOS app with one button and add the following code to the unit. unit Unit1; {$IFDEF FPC} {$mode objfpc}{$H+} {$modeswitch objectivec1} {$ENDIF} interface uses SysUtils, Types, UITypes, Classes, Variants, FMX_Types, FMX_Controls, FMX_Forms, FMX_Dialogs {$IFDEF FPC} , iPhoneAll {$ENDIF} ; type TForm1 = class(TForm) Button1: TButton; procedure Button1Click(Sender: TObject); private { Private ...
Favorite? Off-Topic? Anders Ohlsson @ 2011-10-04 21:21


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